ANMIEL C kabelis, 4 daļu kāju komplekts, 3.1A ātras uzlādes USB C tipa lādētāja kabelis, neilona pinums, saderīgs ar Samsung

✅ The cable length is 10 feet, so it is long enough to charge devices in bedrooms, sofas, and offices, even if you are in the back seat of a car. Very suitable for cables of sufficient length, allowing you to enjoy data synchronization and charging anytime, anywhere without worrying about taking the cable anywhere, making your life more convenient. Excellent performance and safer charging can perfectly replace the original USB cable. ✅ 【 3A fast charging and 480Mbps data synchronization 】 Complies with USB C-type specification version 1.1, ensuring a charging capacity of 3A and transmitting up to 480 megabits of data. Our 3A USB C fast charging cable has an 18W (5V/3A) output, which can charge your device 25% faster than other 5V/2A output cables. It only takes 112 minutes to fully charge a 3700mAh phone [Quick charging prompt: 1 You need an OEM or QC3.0 fast charging adapter. Your phone must be charged quickly. ✅ The ANMIEL USB C charger cable is made of double woven nylon and reinforced with a stylish aluminum casing and SR connector. Our C-type charging cable has been tested and can withstand 10000 bends and 100N tension, so you can rely on our cable at any time. ✅ 【 Universal Compatibility 】 10 foot USB A to C cable for fast charging compatible with Samsung Galaxy S10, S10e S10+Plus 5G S8 S8+S9 S9+S8 Plus S9 Plus, Note 8, Note 9, Note 10+Plus 5G, A10e A20, A30, A40s A. 50 A6 A60 A70 A80 M30s A9/9s A9 Star A8s (2018) A6s C9 C7Pro C5Pro. LGG5 G6 G7 V40 V35 ThinQ V30S V30 V20 Stylo 4 5 MotoG7/G7 Plus/G7 Power/G6/G6 Plus (excluding G6 Play) Z Z2 Z3 X4, Pixel 2 XL, etc. (Unable to achieve fast charging for all C-type phones and devices) ✅ You will receive a set of 4 (10 feet+10 feet+10 feet+10 feet) nylon braided Type-C cables with a three-year warranty and lifetime technology. If you have any questions or suggestions, please contact our 24-hour customer service and we will help you solve the problem.